Hey guys. Perhaps, the questions I'm about to ask are obvious, but bear with me.
To those who understand the inner workings of Springfield XD's, I'd like to ask you guys how the various safety features work. First off, as far as I know, there are 4 different "safety" features: 1) trigger safety, 2) grip safety, 3) firing-pin block 4) out-of-battery safety.
First question: When does the firing-pin block "disengage"? Obviously, the firing-pin block disengages at some point during the trigger pull motion. But when? Does it disengage when only the trigger safety and/or grip safety is depressed? Or does the firing-pin disengage in the moments right before the gun goes bang (during the actual trigger pull)?
Secondly: Depending on the first question, how does the trigger safety work exactly? When you depress only the trigger safety, what happens inside the gun? Does it disengage the firing-pin block (possibly answered in first question)? If not, what does the trigger safety do mechanically that qualifies it as a "safety"? Does depressing the trigger safety merely "unlock" the trigger so that depressing the trigger itself can disengage the firing-pin?
Third: Again, depending on the questions above... Since there is both a trigger safety and a grip safety, are they connected in any way? Is it required for the grip safety to be depressed first, in order to depress the trigger safety (vice versa)?
As you can see, I don't know much about the specifics to how everything functions in the XD, so you guys can answer these questions in whichever order makes sense. Hopefully after then, all of the redundant questions I asked will be ironed out. Thanks in advance!