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Old July 7th, 2006, 01:56 PM   #1
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Calculating stopping percentage with multiple shots...

I thought some would find this interesting, albiet possibly moot...

In many previous discussions regarding One Stop Shots, aside from the debate of the relevance of the data, I found that many people were openly wondering about the effectiveness of multiple shots. This especially came into play during discussions of FMJ or ball ammunition.

The logic frequently went as such: if my 230gr .45ACP bullet has a 60% chance to get an OSS, then if I hit them twice according to the parameters (COM, etc) then I would have a 120% chance of stopping them... 60%+60% = 120%. Well, not quite :)

The following equasion is one that you would use:

1 - (1-X)^n (the "^" is meant to be superscript, i.e. to the "Nth power")

X = the percent chance that the action occurs with one attempt (i.e. 50% = .5)

n = the number of attempts.

---

Therefore, with the aforementioned 60% OSS combined with two shots, we would have 1-(1-.6)^2 or .84... or an 84% chance to get a stop with 2 COM shots of ball. Again, IF the shots are placed according to the study AND if 60% is the correct OSS value (I think it was higher).

Nonetheless, some food for thought.

Cheers
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Old July 7th, 2006, 02:31 PM   #2
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Thats just shows the need for a 3 shot shoot
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Old July 7th, 2006, 02:50 PM   #3
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I'm afraid there are so many variables in a shooting that percentages and statistics don't really mean much.

It seems that all bullets work and all bullets fail. When they work and fail seems to be very, very difficult to analyze because of the great number of variables and relatively small numbers of similar cases.
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Old July 7th, 2006, 02:55 PM   #4
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Interesting to try and quantify this Erik but indeed - the number of variables we really need to include or introduce make it very hard to see a useful and reliable result.

The only possibly reliable parameter is the one - ''shoot until the threat ceases''
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Old July 7th, 2006, 03:14 PM   #5
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Unfortunately I don't really understand the concept of a "One Shot Stopping Percentage". It depends so much on where the round hits that it would seem almost impossible to do much more than keep a large database of shootings, calibers, and "stops" that won't really have any bearing on the next shooting incident.

A shot from a .22LR between one's "headlights" will have more effect than a .45acp that hits one in the "love handles" or other mostly fat tissue part of the body. Since there aren't many that carry .22LR chambered weapons the round is under-represented in the "database". The problem with statistics is that the sampling is usually skewed in favor of popular rounds.

I don't advocate using .22 or .25acp rather than larger calibers, I merely use them to illustrate the absurdity of trying to calculate the so called One Shot Stopping "Index". Doesn't it really boil down to shot placement?
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Old July 8th, 2006, 08:23 AM   #6
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Krept-
that seems to assume independent trials, which is an heroic assumption if you are getting shot. Think of it as the probability you are stopped with one shot given n one shot stop attempts...
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Old July 8th, 2006, 09:26 AM   #7
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krept, read your post several times and just hafta say that I don't understand it at all. I'm not saying that it is flawed. Hell,I don't understand it enough to debate it.

FMJ.... I don't understand why some people will use them for CC. Now I don't claim to be an authority on the matter but I feel that everyone knows the difference between penetration and expansion. If you want a bullet to penetrate you don't want it to expand.(African big game solids,and/or hard cast)If you want a bullet to expand you design the nose with something that starts the expansion process very early in the penetration process.(a ball,polycarbonate tip,HP,wax.etc.)Something that will push the nose open and start the mushroom process.

Now I also understand that all else being equal, two bullets that don't exit the target,one HP and the other FMJ,dump the same ammount of energy. Its just spread over more distance and over a longer period of time.

If a person is using such a low powered weapon(for CC) that they feel that they need a FMJ just to get the proper penetration,then I feel that they need to step up a caliber or two.

Hittin 'em more than once......If the ballistics table sez that one shot with caliber X,using bullet X,traveling at Xfps,produces X ammount of terminal energy,then I can't understand why the figures can't simply be doubled. This,provideing the BG isn't shot thru the same hole. And even if he is,if the bullet dosen't exit.

For me it's less penetration and I want energy dump over a shorter period of time with a larger wound channel(this,given we can't have the best of both worlds). The FBI(or other statistics guru's) say you gotta put it in 12". Take a 12" ruler to your buddy. Have him turn sideways and figure how far a 12" penetration will take the bullet. Now I understand the bullet might have to go thru a bicept before the chest and all the other bad places the you could hafta hit him. Still,to me a foot is extreme. I feel that COM, either front or back,8"would be plenty.(with massive and quick,wound channel)

Again,I don't claim to be an expert on ballistics,terminal or otherwise. These are just my feelings on the much debated subject. -------
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Old July 8th, 2006, 09:34 AM   #8
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Quote:
Originally Posted by krept
...The logic frequently went as such: if my 230gr .45ACP bullet has a 60% chance to get an OSS, then if I hit them twice according to the parameters (COM, etc) then I would have a 120% chance of stopping them... 60%+60% = 120%. Well, not quite :)

The following equasion is one that you would use:

1 - (1-X)^n (the "^" is meant to be superscript, i.e. to the "Nth power")

X = the percent chance that the action occurs with one attempt (i.e. 50% = .5)

n = the number of attempts.

---

Therefore, with the aforementioned 60% OSS combined with two shots, we would have 1-(1-.6)^2 or .84... or an 84% chance to get a stop with 2 COM shots of ball. Again, IF the shots are placed according to the study AND if 60% is the correct OSS value (I think it was higher).

Nonetheless, some food for thought.

Cheers
krept,

I think we, I know I, may have missed part of your point, which BTW was well made. That was the math of combined percentages assuming similar effectiveness of bullets. There is much misunderstanding about percentages, etc. and probably even moreso about the stopping effects of bullets.

But, while the math is correct, it doesn't, and we can't, take into account mathematically, the way an animal or human is going to react to being shot.
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Old July 8th, 2006, 09:40 AM   #9
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Shoot to stop. Don't count your shots.

Must be an engineer or math major type.
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Old July 8th, 2006, 10:33 AM   #10
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Here is my formula for stopping.... Shoot till the target is no longer a threat. Handgun and even rifle rounds are not effective 1 shot stoppers unless CNS is hit. Rifle rounds may give you the luxury of waiting for 1 shot to take effect. (distance ,cover, ect)
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