In many previous discussions regarding One Stop Shots, aside from the debate of the relevance of the data, I found that many people were openly wondering about the effectiveness of multiple shots. This especially came into play during discussions of FMJ or ball ammunition.

The logic frequently went as such: if my 230gr .45ACP bullet has a 60% chance to get an OSS, then if I hit them twice according to the parameters (COM, etc) then I would have a 120% chance of stopping them... 60%+60% = 120%. Well, not quite

The following equasion is one that you would use:

1 - (1-X)^n (the "^" is meant to be superscript, i.e. to the "Nth power")

X = the percent chance that the action occurs with one attempt (i.e. 50% = .5)

n = the number of attempts.

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Therefore, with the aforementioned 60% OSS combined with two shots, we would have 1-(1-.6)^2 or .84... or an 84% chance to get a stop with 2 COM shots of ball. Again, IF the shots are placed according to the study AND if 60% is the correct OSS value (I think it was higher).

Nonetheless, some food for thought.

Cheers